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Northern International School Final Examination, June 2011 STD-VI Subject: mathematics Time: 2 Hours Total Marks: 70 1. solve the sideline expressions: (1 × 5=5 marks) i) x(2a b) + y(b 2a) ii) x(2a + b) + 4(2a b) iii) x(a + b + c) -2y(a + b + c) iv) 2x (a b) (a + b) v) 2x (a b) + (a + b) 2. resolve: - (2 × 5=10 marks) i) x2 + 5x + 6 ii) x2 5x + 6 iii) t2 7t 18 iv) x2 + 11x + 18 v) x2 10xy 11y2 3. measure the following: - (2 × 5=10 marks) i) 5 ¾ - 2 5/6 1 8/15 + 4 7/20 ii) 4/3/5 1/2/15 2/7/9 2/45 iii) 5 ¼ ÷ 2/4/5 ÷ 1/ 7/9 iv) 5 ¼ × 3/3/5 ÷ 2/ 1/10 v) 2/3 × 5/7 4. Find the values of the unknown in one at a time equation: (2 × 5 = 10 marks) i) ½ a 1/3 a = 2 ii) X + x/5 = 12 iii) 3(2a + 3) = 4a + 3 iv) 2(c 4) = 3(c 2) v) 3 x /5 3/7 = 5/7 5. Solve separately of the following: - (2 × 5= 10 marks) i.) If V = 1/3 Ah, mark V when A = 43 and h = 6 ii.) If F = 9c/5 + 32, Find F when C = 30 iii.) If S = 4?r2, mark S when r = 10½ iv.) If k = (x + y) ÷ 3, commence x when k = 12 and y = 4 v.) If T = ?(R2 r2), find T when R = 4 and r = 3 6.

Solve the following simultaneous equations: - (3 × 5= 15 marks) ! i) x + y = 8 ii) 2x + y = 7 x y = 4 3x + y = 10 iii) 3x + 7y = 10 iv) 5x + 3y = 7 4x y = 3 4x + 5y = 3 v) 3x + y = 8 5x 3y = 11 7. Triangles on the same basal and between the same parallels (hence, of the same altitude) argon equal in area. Prove this theorem. (10 marks)If you want to get a full essay, ordination it on our website: BestEssayCheap.com

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